Chemistry Form 4 Activity 3.11 -

(a) Mass of CuO = 20.10 - 16.20 = 3.90 g Mass of Cu = 19.50 - 16.20 = 3.30 g Mass of O = 3.90 - 3.30 = 0.60 g (b) Moles Cu = 3.30/64 = 0.0516 Moles O = 0.60/16 = 0.0375 Ratio = 0.0516/0.0375 = 1.376 (This is 1.4 – interesting, not perfect 1. This indicates experimental error, but theoretically it aims for 1:1). For perfect theory: Should be 1.0. (c) CuO

By understanding the principles and procedures outlined in this article, students can successfully complete Chemistry Form 4 Activity 3.11 and develop a deeper understanding of volumetric analysis and titration techniques. chemistry form 4 activity 3.11