Statics Of Rigid Bodies Ferdinand Singer 42: Free

A beam 6 m long carries a 10 kN concentrated load at 2 m from left end, a 20 kN load at 4 m from left end, and a uniformly distributed load of 5 kN/m over the entire span. Find the resultant and its location from the left support.

In many editions and solution manuals for Singer's Engineering Mechanics , Problem 242 is a frequently cited example involving .

| Aspect | Review | |--------|--------| | Difficulty | Medium – good for practice after learning resultants | | Relevance | High – typical board exam or engineering mechanics problem | | Clarity | Clear statement, but requires careful reading of load positions | | Time to solve | 10–15 minutes if done manually | Statics Of Rigid Bodies Ferdinand Singer 42

$$P = 100 \cdot \frac\sin 30 - 0.30 \cos 30\cos 30 + 0.30 \sin 30$$ $$P = 100 \cdot \frac0.5 - 0.25980.8660 + 0.15$$ $$P = 100 \cdot \frac0.24021.016$$ $$P \approx 23.64 \text lbs$$

By taking moments about one end of the bar (to eliminate one unknown), you can solve for the other force, then plug it back into the force equation. Why Singer's Text Remains Relevant A beam 6 m long carries a 10

): The sum of all moments (torques) about any point must be zero to prevent rotation. Breaking Down "Problem 42" (or 242)

Solving the above equation for $P$ yields the general formula: | Aspect | Review | |--------|--------| | Difficulty

If the problem asks for the magnitude of the force given specific numbers (e.g., $\mu = 0.30$, $\theta = 30^\circ$, $W = 100 \text lbs$), you plug them in.